<div class="gmail_quote">On Sun, Dec 6, 2009 at 5:47 PM, Tobias Knerr <span dir="ltr"><<a href="mailto:osm@tobias-knerr.de">osm@tobias-knerr.de</a>></span> wrote:<br><blockquote class="gmail_quote" style="border-left: 1px solid rgb(204, 204, 204); margin: 0pt 0pt 0pt 0.8ex; padding-left: 1ex;">
<div class="im">Pieren wrote:<br>
> Could someone deliver a script that could make this automatically for<br>
> me :"take all elements where I am the last contributor but not the<br>
> only one then delete and recreate them identically under my user<br>
> account then all my efforts are saved at the licence transition" ?<br>
<br>
</div>In my opinion, whether your data is derived from other data isn't<br>
determined by having the same object ID. If I completely remove all tags<br>
from a node, move it somewhere else and add new tags, then it's most<br>
likely not derived from the previous work. If I add a tag to a road,<br>
then it is derived from previous work, and this doesn't change at all if<br>
I choose to copy the road and delete the original.<br>
<br>
Using the object history is just an approximation based on the<br>
assumption that mappers will usually keep an object if they are<br>
improving existing data, and create new objects if they add completely<br>
new information. It's not really possible for an automated process to do<br>
anything else.<br>
<font color="#888888"><br></font></blockquote><div>Actually even this doesn't work. If a way is split into two (using JOSM) then the database does not record any information about the split and the history is kept with only one of the ways.<br>
<br>This means that the history and original attribution for half of all the split ways is just not there. I don't think there's going to be a way of deleting all the data for those people who don't accept the new license.<br>
<br><br><br><br><br> </div><blockquote class="gmail_quote" style="border-left: 1px solid rgb(204, 204, 204); margin: 0pt 0pt 0pt 0.8ex; padding-left: 1ex;"><font color="#888888">
Tobias Knerr<br>
</font><div><div></div><div class="h5"><br>
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