[Tagging] healthcare: attribute or stand alone tag? (was Re: Feature Proposal - RFC - Blood donation 2)

André Pirard A.Pirard.Papou at gmail.com
Mon Jun 29 21:41:11 UTC 2015


On 2015-06-29 18:55, Holger Jeromin wrote :
> André Pirard wrote on 29.06.2015 17:08:
>> Ruben Maes <ruben.maes96 at gmail.com> Wrote in message:
>>> After the proposal Donation was rejected, I tried to address the
>>> issues that were raised in a new proposal using
>>> healthcare=blood_donation:
>>> https://wiki.openstreetmap.org/wiki/Proposed_features/Blood_donation_2
>>> You are of course welcome to point out any flaws.
>> Like I said, could you please in your proposal *stress* that healthcare
>> is not an object but an attribute of an object.
>> There is no such thing as "a healthcare" on a map but a building can be
>> used for healthcare.
>> Then, healthcare is an attribute of that building.
>> Out of curiosity, I've had a look at Key:healthcare
>> <https://wiki.openstreetmap.org/wiki/Key:healthcare>  and it's exactly
>> what it says:
>>> ... add *healthcare*=* to to an area that has building
> Is this (5 years later) really still true? I am quite happy with my
> (indoor tagging) node:
>
> http://www.openstreetmap.org/node/1227761407#map=19/50.77699/6.04469
What is "this"?
My remark concerns mainly areas (buildings).
But it's also interesting to know what a node represents (what
healthcare is an attribute of).
> Is a restaurant or hotel also a attribute to an object?
Of course it is.
They are the attributes that make a building (usually) suitable for
catering and accommodation.

>> You should give an example of for example a school where blood_donation
>> takes place:
>>
>> building=school
>> or
>> building=yes
>> school=yes
> Eeks, not a good example tag :)
If you think so, you should say why and what you propose.
Not just the usual "no".
I think that such a page should teach the reader how to tag healthcare
taking place in a school.
>> and
>> healthcare=blood_donation
>> or
>> healthcare:blood_donation=yes
>> healthcare:anything_else=yes  (if there are several)
>




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