[Talk-GB] overpass query involving pubs
roland.olbricht at gmx.de
Fri Oct 27 04:40:38 UTC 2017
> I am confused by this.
> I understood ( x; y; ); to be the union of x and y. Rather than x
> passing its results onto y. What am i missing.
It is both at the same time. Given an example like
the node(w)-part should depend on the way[foo=bar] part.
And we want both (the ways and the nodes they depend on) in the result.
The rest is a trade-off what is more frequent.
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