[GraphHopper] Geoposition of an edge

[Peter K]

Hey Phil,

I have really no idea - what is l_position.intValue() - is this the
edgeId? Also probably use fetchWayGeometry(2) which will include the
junction nodes of the edge.

Regards,
Peter.


> Hi, 
>
> I have create a short testing code:
>
>         EdgeIteratorState l_state = CGraphHopper.getInstance().getEdgeIterator(l_position.intValue());
>         PointList l_points = l_state.fetchWayGeometry(0);
>
>         //double l_latitude  = l_points.getLatitude(0)  + l_position.intValue() * ( l_points.getLatitude(l_points.size()-1)  - l_points.getLatitude(0) );
>         //double l_longitute = l_points.getLongitude(0) + l_position.intValue() * ( l_points.getLongitude(l_points.size()-1) - l_points.getLongitude(0) );
>
>         return new GeoPosition(l_points.getLatitude(0), l_points.getLongitude(0));
>
> and the first point in the point list is around 200-300 km from the edge which is stored in my route edge list. The first item in my route edges is:
> [51.80351990955801, 10.348262786865234]
> but the first item on fetchGeometry returns
> [52.48197732452998, 7.9807603652945245]]
>
> Dou you have an idea?
>
> Phil
>
>
>
> Am 29.04.2014 um 15:55 schrieb Peter K <peathal at yahoo.de>:
>
>> Hey Phil,
>>
>>
>>> I think it is „fetchWayGeometry“ ? The fetch option should result a point list and in which way can you get a tip to get the correct point position. I know the edge has got e.g. 20 cells and I need the geoposition of the 5th cell. I don’t understand the matching between the point list and cell number.
>> You'll have to implement your own custom logic :)
>>
>> E.g. just pick the first and the last point of that pointlist and
>> calculate latDistance and lonDistance. Then iterate in a loop
>>
>> for(cell : cellsForThatEdge) {
>>  cell.set(lat, lon)
>>  lat+=latDistance
>>  lon+=lonDisatnce
>> }
>>
>>> How can I get an EdgeIterator from an EdgeID, does exists anything like this.graph.getEdgeIterator(<EdgeID>)?
>> via graph.getEdgeProps(edgeId, Integer.MIN_VALUE)
>
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